Unit Test 4: Geometry
Overview
This page provides an Overview of Mathematics for CBSE Class 10. Topics covered include key concepts, formulas, and problem-solving techniques. All content is aligned with the NCERT syllabus for Board Exam preparation.
Class 10 Mathematics (Standard)
General Instructions:
- The question paper consists of 19 questions divided into 5 sections: A, B, C, D, and E.
- Section A: 8 MCQs of 1 mark each.
- Section B: 4 Short Answer questions of 2 marks each.
- Section C: 4 Short Answer questions of 3 marks each.
- Section D: 1 Case Study based question of 4 marks.
- Section E: 2 Long Answer questions of 4 marks each.
- Use of calculators is not permitted.
A scale drawing of an object is the same shape as the object but a different size. The scale of a drawing is a comparison of the length used on a drawing to the length it represents. The ratio of the length of the image to the corresponding length of the object is called the scale factor.
(i) If a triangle has sides 3 cm, 4 cm, 5 cm and a similar triangle has a scale factor of 2, what are the sides of the new triangle? (1 Mark)
(ii) What is the ratio of the areas of two similar triangles if the scale factor is k? (2 Marks)
(iii) If the shadow of a stick 1m long is 40cm, and the shadow of a tower is 20m, what is the height of the tower? (1 Mark)
0 / 8 (MCQ)
(Subjective answers submitted for review)
Solution Key (MCQs)
By BPT, AD/DB = AE/EC ⇒ 1.5/3 = 1/EC ⇒ 1/2 = 1/EC ⇒ EC = 2 cm.
Radius = √(OQ² - PQ²) = √(25² - 24²) = √(625 - 576) = √49 = 7 cm.
Ratio of areas = (Ratio of sides)² = (6/8)² = (3/4)² = 9/16.
Half chord length = √(5² - 3²) = √(25-9) = 4. Total length = 2 × 4 = 8 cm.
AD/AB = AE/AC ⇒ 3/(3+5) = AE/4.8 ⇒ 3/8 = AE/4.8 ⇒ AE = (3 × 4.8)/8 = 1.8 cm.
∠AOB = 180 - 80 = 100°. ∠POA = 1/2 ∠AOB = 50°.
Diagonals bisect at 90°. Half diagonals are 8 and 6. Side = √(8² + 6²) = √100 = 10 cm.
∠PTQ + ∠POQ = 180° ⇒ ∠PTQ = 180 - 110 = 70°.